SOLUTION: find the value for sin(x/2) if the following conditions hold tan(x)=-4/3 and x is in quadrant IV

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Question 1035159: find the value for sin(x/2) if the following conditions hold tan(x)=-4/3 and x is in quadrant IV
Found 2 solutions by solver91311, Alan3354:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Half-angle formula:



But that requires that we know and we only have and that

However, we also know that



So







Then, using the Pythagorean Identity:





And then



But since



Just plug this value into the half-angle formula and do the arithmetic. Don't forget to rationalize your denominator. Also, half of a QIV angle is in QII, so the sine is positive.

John

My calculator said it, I believe it, that settles it


Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
find the value for sin(x/2) if the following conditions hold tan(x)=-4/3 and x is in quadrant IV
---------------
tan = y/x
r = sqrt(y^2 + x^2) = 5
sin(x) = y/r = -4/5
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sin^2(x/2) = (1 - cos(x))/2 ***** Much simpler than the sin(x/2)
cos(x) = x/r = 3/5 --- cosine is + in Q4
---
sin^2(x/2) = (2/5)/2 = 1/5
sin(x/2) = sqrt(1/5) = sqrt(5)/5