SOLUTION: 0Sin^2(x)-sin(x)= Find the possible solutions between 0 and 2pi

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Question 1035049: 0Sin^2(x)-sin(x)=
Find the possible solutions between 0 and 2pi
Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
Hi there,
Solve:
Sin^2(x)-sin(x)=0 0<=x=<2π
sin(x)(sin(x) - 1) = 0
sin(x) = 0
x = 0, π, 2π
sin(x) = 1
x = π/2
Hope this helps :-)