Let the number of nickels be x
Let the number of dimes be y
Value Value
Type Number of of
of of EACH ALL
coin coins coin coins
-------------------------------------------
nickels x $0.05 $0.05x
dimes y $0.10 $0.10y
-------------------------------------------
TOTALS 70 ----- $4.65
The first equation comes from the "number of coins" column.
x + y = 70
The second equation comes from the last column.
0.05x + 0.10y = 4.65
Get rid of decimals by multiplying every term by 100:
5x + 10y = 465
So we have the system of equations:
.
We solve by substitution. Solve the first equation for y:
x + y = 70
y = 70 - x
Substitute (70 - x) for y in 5x + 10y = 465
5x + 10(70 - x) = 465
5x + 700 - 10x = 465
-5x + 700 = 465
-5x = -235
x = 47 = the number of nickels.
Substitute in y = 70 - x
y = 70 - (47)
y = 23 dimes.
Checking: 47 nickels is $2.35 and 23 dimes is $2.30
That's 70 coins.
And indeed $2.35 + $2.30 = $4.65
Edwin