SOLUTION: Is it possible to bend a 12cm length of wire to form the base and perpendicular height of a right-angled triangle with an area of 20 cm's Squared?

Algebra ->  Triangles -> SOLUTION: Is it possible to bend a 12cm length of wire to form the base and perpendicular height of a right-angled triangle with an area of 20 cm's Squared?      Log On


   



Question 1034612: Is it possible to bend a 12cm length of wire to form the base and perpendicular height of a right-angled triangle with an area of 20 cm's Squared?
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
h for hypotenuse
x for one dimension
y for other dimension
system%28x%2By%2Bh=12%2Cx%5E2%2By%5E2=h%5E2%2C%281%2F2%29xy=20%29
See what you can find.


A way to begin may be
h=12-x-y
-
x%5E2%2By%5E2=%2812-x-y%29%5E2
x%5E2%2By%5E2=%2812-%28x%2By%29%29%5E2=12%5E2-24%28x%2By%29%2B%28x%2By%29%5E2
x%5E2%2By%5E2=144-24x-24y%2Bx%5E2%2B2xy%2By%5E2
Notice x^2 and y^2 on both sides.
0=144-24x-24y%2B2xy


Continue with the system system%28%281%2F2%29xy=20%2C24x%2B24y-2xy=144%29..............