Question 1034559: A spherical hailstone grows in a cloud. The radius of the hailstone is increasing at the rate of 0.2mm/s. a) Determine a formula for the radius, r, of the hailstone at time t, assuming that the radius of the hailstone is 0 mm at t = 0 b) Express the volume, V, of the hailstone in terms of its radius, r c) Determine a formula for (V(r))(t), and explain what it represents
What i have so far is a) v(r) = 0.2t b) V = 4/3*pi*r^3, v(r) = 4/3pi(0.2t)^2 c) i am still stuck on part c) and what it means
Answer by robertb(5830)   (Show Source):
You can put this solution on YOUR website! For (a), change v(r) to r(t). In (c), change (0.2t)^2 to (0.2t)^3. V(r(t)) gives a way of finding the volume with respect to time t.
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