SOLUTION: Solve each equation by finding the value of x to the nearest degree. 1. Arcsin 1 = x 2. Cos^-1 square root 3/2 =x 3. x= tan^-1 (- squareroot 3/3) 4. x= Arccos sqaureroot 2/

Algebra ->  Trigonometry-basics -> SOLUTION: Solve each equation by finding the value of x to the nearest degree. 1. Arcsin 1 = x 2. Cos^-1 square root 3/2 =x 3. x= tan^-1 (- squareroot 3/3) 4. x= Arccos sqaureroot 2/      Log On


   

Question 1034535: Solve each equation by finding the value of x to the nearest degree.
1. Arcsin 1 = x
2. Cos^-1 square root 3/2 =x
3. x= tan^-1 (- squareroot 3/3)
4. x= Arccos sqaureroot 2/2
5. x= Arctan (-squareroot 3)
6. Sin^-1= (-1/2)= x

Answer by ikleyn(52787) About Me  (Show Source):
You can put this solution on YOUR website!
.
Solve each equation by finding the value of x to the nearest degree. 

1. Arcsin 1 = x.

   They ask you: what is the angle  alpha,  if  sin%28alpha%29 = 1 ?
   The answer is:  alpha = 90°.  Or  arcsin%281%29 = 90°.   Or x = 90°.                


2. Cos^-1 square root 3/2 =x 

   I will rewrite it in this equivalent form:  arccos%28sqrt%283%29%2F2%29 = x

   They ask you: what is the angle  alpha, if  cos%28alpha%29 = sqrt%283%29%2F2.
   The answer is:  alpha = 30°.  Or  arccos%28sqrt%283%29%2F2%29 = 30°.   Or x = 30°.  


3. x= tan^-1 (- squareroot 3/3) 

   I will rewrite it in this equivalent form:  arctan%28-sqrt%283%29%2F3%29 = x

   They ask you: what is the angle  alpha, if  tan%28alpha%29 = -sqrt%283%29%2F3.
   The answer is:  alpha = -60° = 300°.  Or  arctan%28-sqrt%283%29%2F3%29 = -60°.   Or x = -60°.  


Now try to complete the assignment following to the same scheme.


4. x= Arccos sqaureroot 2/2 
5. x= Arctan (-squareroot 3) 
6. Sin^-1= (-1/2)= x