SOLUTION: given g(t) -(T^2 + 2)/(2t-7), find g'(s)

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Question 1034511: given g(t) -(T^2 + 2)/(2t-7), find g'(s)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
g(t) -(t^2 + 2)/(2t-7), find g'(t)
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g'(t) = [(2t-4)(-2t) + (t^2+2)(2)] / (2t-7)^2
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g'(t) = [-2t^2+4 + 2t^2+4]/(2t-7)^2
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g'(t) = 8/(2t-7)^2
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Cheers,
Stan H.
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