SOLUTION: two cyclists, 90 km apart, start riding toward each other at the same time. one cycles twice as fast as the other. If they meet 2 hours later at whatspeed are they traveling?
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Question 103445: two cyclists, 90 km apart, start riding toward each other at the same time. one cycles twice as fast as the other. If they meet 2 hours later at whatspeed are they traveling? Answer by checkley75(3666) (Show Source):
You can put this solution on YOUR website! 90=(X+2X)2
90=3X*2
90=6X
X=90/6
X=15 KM/H FOR THE SLOWER BIKER.
2*15=30 FOR THE FASTER BIKER.
PROOF
90=(30+15)2
90=45*2
90=90
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