SOLUTION: Find all solutions of the equation in the interval [0, 2pi). -sinx=-cos^2x-1 Write your answer in radians in terms of pi.

Algebra ->  Trigonometry-basics -> SOLUTION: Find all solutions of the equation in the interval [0, 2pi). -sinx=-cos^2x-1 Write your answer in radians in terms of pi.      Log On


   



Question 1034388: Find all solutions of the equation in the interval [0, 2pi).
-sinx=-cos^2x-1
Write your answer in radians in terms of pi.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
-sinx=-cos^2x-1
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cos^2 = 1 - sin^2