SOLUTION: Please help me solve this equation, answering in a+bi form: (16-16i)^0.25

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: Please help me solve this equation, answering in a+bi form: (16-16i)^0.25      Log On


   



Question 1034297: Please help me solve this equation, answering in a+bi form: (16-16i)^0.25
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Please help me solve this equation, answering in a+bi form: (16-16i)^0.25
-----------
That's not an equation. There's no equal sign, and there's no variable to solve for.
---
If you want to find the 4 4th roots:
(16-16i) --> 16sqrt(2)cis(315)
----
The 4 4th roots are:
2%2Aroot%288%2C2%29cis%2878.57%29%29
+ 360/4:
2%2Aroot%288%2C2%29cis%28168.57%29%29
+ 360/4:
2%2Aroot%288%2C2%29cis%28258.57%29%29
+ 360/4:
2%2Aroot%288%2C2%29cis%28348.57%29%29
--------------
a+bi form
root%288%2C512%29%2A%28cos%2878.57%29+%2B+i%2Asin%2878.75%29%29
Do the form for the others the same way.