SOLUTION: When an object moves in a circular path, the centripetal force F varies directly as the square of the velocity v and inversely as the radius r of the circle. If F=200 when v=6 and
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-> SOLUTION: When an object moves in a circular path, the centripetal force F varies directly as the square of the velocity v and inversely as the radius r of the circle. If F=200 when v=6 and
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Question 1034274: When an object moves in a circular path, the centripetal force F varies directly as the square of the velocity v and inversely as the radius r of the circle. If F=200 when v=6 and r=5, find F when v=4 and r=8.
Help would be so appreciated. Thank you Answer by ikleyn(52781) (Show Source):
You can put this solution on YOUR website! .
When an object moves in a circular path, the centripetal force F varies directly as the square of the velocity v and
inversely as the radius r of the circle.
If F=200 when v=6 and r=5, find F when v=4 and r=8.
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First statement is translated as
F = (1)
with the constant k.
Next statement ". . . F=200 when v=6 and r=5" is translated as
200 = . (2)
(simply plug in your data into the formula (1)). Simplify (2) to get
200 = and then obtain k = = .
Now "find F when v=4 and r=8."
Use the formula (1) and the value k = :
F = = = 34.72.
