SOLUTION: Find tan t given that sin t=3/5 and cot t < 0

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Question 1034092: Find tan t given that sin t=3/5 and cot t < 0
Found 3 solutions by josmiceli, stanbon, MathTherapy:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Thinking just about signs, it is given that
sin(t) is positive and cot(t) is negative.
--------------------
The sin function is positive in the
1st and 2nd quadrants
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The cot function is negative in the
2nd and 4th quadrants
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+t+ must be an angle in the 2nd
quadrant
The horizontal component is +4+
since +5%5E2+-+3%5E2+=+4%5E2+
--------------------
+tan%28t%29+=+-3%2F4+

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find tan t given that sin t=3/5 and cot(t) is negative, t is in QII
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Since sin = y/r, y = 3 and r = 5
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Then x = -sqrt[5^2-3^2] = -4
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tan(t) = y/x = -4/5
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Cheers,
Stan H.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Find tan t given that sin t=3/5 and cot t < 0
sin is positive (> 0), and cot is negative (< 0), so t is in the 2nd quadrant. Also since cot is < 0, tan will also be < 0
sin+%28t%29+=+O%2FH+=+3%2F5+=+y%2Fr
Since y = 3 and r = 5, this is a 3-4-5 Pythagorean triple. Hence, x = - 4 (x is < 0 in the 2nd quadrant)