SOLUTION: mr ishiwaka left kanas city, missouri, at 3:00 p.m. and arrives in tulsa oklahoma at 8:00 p.m., driving the distance of approximently 240 miles.during his trip, he took a one hour
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-> SOLUTION: mr ishiwaka left kanas city, missouri, at 3:00 p.m. and arrives in tulsa oklahoma at 8:00 p.m., driving the distance of approximently 240 miles.during his trip, he took a one hour
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Question 1034050: mr ishiwaka left kanas city, missouri, at 3:00 p.m. and arrives in tulsa oklahoma at 8:00 p.m., driving the distance of approximently 240 miles.during his trip, he took a one hour dinner break. what was his average speed in miles per hour? Answer by fractalier(6550) (Show Source):
You can put this solution on YOUR website! If he drove from 3 pm to 8 pm and took an hour break, he drove for 4 hours total...
Speed = distance / time = 240 miles / 4 hours = 60 mph on average
