SOLUTION: Find the equation of a line parallel to 3x+4y=7 intersect the positive x axis and positive y axis so that the triangle formed by the line and these axes has an area of 6. Than

Algebra ->  Graphs -> SOLUTION: Find the equation of a line parallel to 3x+4y=7 intersect the positive x axis and positive y axis so that the triangle formed by the line and these axes has an area of 6. Than      Log On


   

Question 1033772: Find the equation of a line parallel to 3x+4y=7 intersect the positive x axis and positive y axis so that the triangle formed by the line and these axes has an area of 6.

Thank you in advanced!
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
The line would have to have the form 3x+4y = k for some undetermined constant k > 0, as wanted.
The x-intercept of this line is k/3, while its y-intercept is k/4.
The area is thus 6+=+%281%2F2%29%28k%2F4%29%28k%2F3%29+=+k%5E2%2F24
==> k%5E2+=+144 ==> k = 12.
Therefore the equation of the line is 3x+4y=12.