SOLUTION: The function f(x)=x^2-9x+14 has a maximum or minimum value? What is the value?

Algebra ->  Functions -> SOLUTION: The function f(x)=x^2-9x+14 has a maximum or minimum value? What is the value?      Log On


   



Question 1033705: The function f(x)=x^2-9x+14 has a maximum or minimum value? What is the value?
Found 3 solutions by josgarithmetic, josmiceli, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Based on y=x%5E2 so vertex minimum. The vertex occurs in the exact middle of the x-axis intercepts, but does not occur on the axis.

Try finding the vertex putting function into standard form.
y=x%5E2%2Bbx%2Bc
x%5E2%2Bbx%2B%28b%2F2%29x%2B%28b%2F2%29%5E2%2Bc-%28b%2F2%29%5E2
y=%28x%2Bb%2F2%29%5E2%2Bc-b%5E2%2F4
This general form indicates that vertex is ( -b/2, c-b^2/4 );


This is y=14-%28-9%29%5E2%2F4=14-81%2F4=%2856-81%29%2F4=-25%2F4=highlight%28-6%261%2F4%29.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+f%28x%29+=+x%5E2+-+9x+%2B+14+
The vertex ( either maximum or minimum )
is at +x%5Bv%5D+=+-b%2F%282a%29+ when the form is:
+a%2Ax%5E2+%2B+b%2Ax+%2B+c+
+a+=+1+
+b+=+-9+
+x%5Bv%5D+=+-%28-9%29+%2F+%28+2%2A1+%29+
+x%5Bv%5D+=+9%2F2+
------------------------
Another way to see this is: the vertex is midway
between the roots
+f%28x%29+=+0+
+f%28x%29+=+%28+x-7+%29%2A%28+x-2+%29+
+x+=+7+
+x+=+2+
-------------
The midway point is at:
+x%5Bv%5D+=+%28+7+%2B+2+%29+%2F+2+
+x%5Bv%5D+=+9%2F2+
---------------------
Plug this value back into equation
+f%289%2F2%29+=+%289%2F2%29%5E2+-+9%2A%289%2F2%29+%2B+14+
+f%289%2F2%29+=+81%2F4+-+81%2F2+%2B+14+
+f%289%2F2%29+=+81%2F4+-+162%2F4+%2B+56%2F4+
+f%289%2F2%29+=+-25%2F4+
-------------------
The vertex is at ( 9/2, -25/4 ), which means it must be
a minimum since there are 2 roots on either side which
are above the vertex.
--------------------
Here's the plot:
+graph%28+400%2C+400%2C+-2%2C+10%2C+-8%2C+10%2C+x%5E2+-+9x+%2B+14++%29+

Answer by ikleyn(52782) About Me  (Show Source):
You can put this solution on YOUR website!
.
This quadratic function has the coefficient 1 at x%5E2.
Hence, the parabola is open upward.


Memorize it:

   If the coefficient at x%5E2 is a positive number, then 
   the quadratic function is a parabola open upward and has a minimum.


   If, in opposite, the coefficient at x%5E2 is a negative number, then 
   the quadratic function is a parabola open downward and has a maximum.