SOLUTION: Find an equation of the hyperbola that satisfies the given conditions. Foci (0,±3 square root 2), length of conjugate axis is 2

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Question 1033592: Find an equation of the hyperbola that satisfies the given conditions.
Foci (0,±3 square root 2), length of conjugate axis is 2
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
The length of conjugate axis = 2b = 2 ==> b = 1.
The hyperbola would take the form y%5E2%2Fa%5E2+-+x%5E2%2Fb%5E2+=+1
==> y%5E2%2Fa%5E2+-+x%5E2%2F1%5E2+=+1, or y%5E2%2Fa%5E2+-+x%5E2+=+1
For a hyperbola, c%5E2+=+a%5E2+%2B+b%5E2 ==> %283%2Asqrt%282%29%29%5E2+=+a%5E2+%2B1
==> 18+=+a%5E2+%2B+1 ==> a%5E2+=+17
Therefore the equation of the hyperbola is y%5E2%2F17+-+x%5E2+=+1.