SOLUTION: TRIANGLE ABC and TRIANGLE XYZ are similar triangles. If BA = x + 7, AC = x + 4, YX = x + 2, and XZ = x + 3, find the value of x.

Algebra ->  Geometry-proofs -> SOLUTION: TRIANGLE ABC and TRIANGLE XYZ are similar triangles. If BA = x + 7, AC = x + 4, YX = x + 2, and XZ = x + 3, find the value of x.      Log On


   



Question 1033540: TRIANGLE ABC and TRIANGLE XYZ are similar triangles. If BA = x + 7, AC = x + 4, YX = x + 2, and XZ = x + 3, find the value of x.
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TRIANGLE ABC and TRIANGLE XYZ are similar triangles. If BA = x + 7, AC = x + 4, YX = x + 2, and XZ = x + 3, find the value of x.
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Since triangles ABC and XYZ are similar, their corresponding sides (side dimensions) are proportional.

In particular,  

abs%28BA%29%2Fabs%28YX%29 = abs%28AC%29%2Fabs%28XZ%29,  or %28x%2B7%29%2F%28x%2B2%29 = %28x%2B4%29%2F%28x%2B3%29.    (1)

To find "x", cross-multiply. You will get

(x+7)*(x+3) = (x+2)*(x+4).

Simplify and solve for x:

x%5E2+%2B+10x+%2B+21 = x%5E2+%2B+6x+%2B+24,   or

4x = 3,

x = 3%2F4.