SOLUTION: (3r-rt/6r^2t)*(3/9-t^2) My answer: r/2r^2t(3+t) I know I'm not supposed to have 2r^2. It should just be 2r, but I don't know exactly how.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: (3r-rt/6r^2t)*(3/9-t^2) My answer: r/2r^2t(3+t) I know I'm not supposed to have 2r^2. It should just be 2r, but I don't know exactly how.      Log On


   

Question 1033446: (3r-rt/6r^2t)*(3/9-t^2)
My answer: r/2r^2t(3+t)
I know I'm not supposed to have 2r^2. It should just be 2r, but I don't know exactly how.
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
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%28%283r-rt%29%2F%286r%5E2t%29%29%2A%28%283%29%2F%289-t%5E2%29%29
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%28%28r%283-t%29%29%2F%286r%5E2t%29%29%2A%28%283%29%2F%289-t%5E2%29%29
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%28%28r%283-t%29%29%2F%28r%286rt%29%29%29%2A%28%283%29%2F%289-t%5E2%29%29 . r divides out of left side
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%28%283-t%29%2F%286rt%29%29%2A%28%283%29%2F%289-t%5E2%29%29
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%28%283%29%283-t%29%29%2F%28%283%29%282rt%29%289-t%5E2%29%29 . 3 divides out
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%283-t%29%2F%28%282rt%29%283-t%29%283%2Bt%29%29 . (3-t) divides out
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%281%29%2F%28%282rt%29%283%2Bt%29%29
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