SOLUTION: Let x, y, and z be nonzero real numbers. Find all possible values of (x)/(|x|) + (y)/(|y|) + (z)/(|z|) + (xyz)/(|xyz|). List your values in increasing order, separated by com

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Let x, y, and z be nonzero real numbers. Find all possible values of (x)/(|x|) + (y)/(|y|) + (z)/(|z|) + (xyz)/(|xyz|). List your values in increasing order, separated by com      Log On


   



Question 1033415: Let x, y, and z be nonzero real numbers. Find all possible values of
(x)/(|x|) + (y)/(|y|) + (z)/(|z|) + (xyz)/(|xyz|).
List your values in increasing order, separated by commas.

Found 2 solutions by ikleyn, Edwin McCravy:
Answer by ikleyn(52792) About Me  (Show Source):
You can put this solution on YOUR website!
.
Let x, y, and z be nonzero real numbers. Find all possible values of
(x)/(|x|) + (y)/(|y|) + (z)/(|z|) + (xyz)/(|xyz|).
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Let F(x,y,z) = x%2Fabs%28x%29 + y%2Fabs%28y%29 + z%2Fabs%28z%29 + %28xyz%29%2Fabs%28xyz%29.


It is clear that it is sufficient to estimate/calculate F(x,y,z) at x = +/-1, y = +/-1 and z = +/-1. In total, there are 8 inputs.

If there are all "+" in the input, the result is 4.

If there is precisely 1 "-" in the input, then the result is 0.

If there are precisely 2 "-" in the input, then the result is 0.

If there are all "-" in the input, then the result is -4.

Answer. The list of all possible values is 4, 0, -4.


Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
x%2Fabs%28x%29%2By%2Fabs%28y%29%2Bz%2Fabs%28z%29%2B%28xyz%29%2Fabs%28xyz%29
Case 1. All three variables positive:  x>0, y>0, z>0

x%2Fx%2By%2Fy%2Bz%2Fz%2B%28xyz%29%2F%28xyz%29

1%2B1%2B1%2B1%22%22=%22%224

Case 2. Two of the variables positive, one negative
By symmetry, it doesn't matter which one is negative,
the answer will be the same.  Say, only y is negative:

x>0, y<0, z>0

x%2Fx%2By%2F%28-y%29%2Bz%2Fz%2B%28xyz%29%2F%28x%28-y%29z%29

1-1%2B1-1%29%22%22=%22%220

Case 3. One of the variables positive, two negative
Also by symmetry, it doesn't matter which one is positive,
the answer will be the same.  Say, only x is positive 

x>0, y<0, z<0

x%2Fx%2By%2F%28-y%29%2Bz%2F%28-z%29%2B%28x%28-y%29%28-z%29%29%2F%28x%28-y%29%28-z%29%29

1-1-1%2B1%29%22%22=%22%220

Case 4. All three negative:  x<0, y<0, z<0

x%2F%28-x%29%2By%2F%28-y%29%2Bz%2F%28-z%29%2B%28xyz%29%2F%28%28-x%29%28-y%29%28-z%29%29

-1-1-1-1%22%22=%22%22-4

In increasing order, separated by commas:

-4,0,4

Edwin