SOLUTION: From a Putnam competition: Evaluate the integral {{{int(ln(x+1)/(x^2+1), dx, 0,1)}}}.
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-> SOLUTION: From a Putnam competition: Evaluate the integral {{{int(ln(x+1)/(x^2+1), dx, 0,1)}}}.
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Question 1033411
:
From a Putnam competition:
Evaluate the integral
.
Answer by
robertb(5830)
(
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):
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Since
,
.
Let
. ==> tanw = x. Now if x = 0, w = 0, and when x = 1,
.
==>
.
Now
=
=
=
.
But
by using the substitution
on the left integral.
Hence