SOLUTION: How would I simplify and state the non-permissible values of these questions? {{{4x/(x+2) + 3/(x+1)}}} 3x/x-4+6/x+2

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Question 1033388: How would I simplify and state the non-permissible values of these questions?
4x%2F%28x%2B2%29+%2B+3%2F%28x%2B1%29
3x/x-4+6/x+2





Found 2 solutions by stanbon, Edwin McCravy:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
simplify and state the non-permissible values of these questions?
4x/(x+2) + 3/(x+1)
The denominators cannot be zero.
x cannot be -2 ; x cannot be -1
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3x/(x-4) + 6/(x+2)
x cannot be 4 ; x cannot be -2
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Cheers,
Stan H.
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Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
4x%2F%28x%2B2%29+%2B+3%2F%28x%2B1%29

Division by zero is not defined in mathematics

So denominators can never be zero, so

The denominator x+2 can never equal to 0,

so we write x+2 ≠ 0 and solve for x
              x ≠ -2

The denominator x+1 also can never equal to 0,

so we write x+1 ≠ 0 and solve for x
              x ≠ -1

On a number line like this 

--------------------------------
-6 -5 -4 -3 -2 -1  0  1  2  3  4

We put open circles at -2 and -1

-------------o--o---------------
-6 -5 -4 -3 -2 -1  0  1  2  3  4

and shade the rest, putting arrows at the ends,
pointing to negative infinity on the left and to
positive infinity on the right:

<============o==o==============>
-6 -5 -4 -3 -2 -1  0  1  2  3  4

The interval notation is an abbreviation of the
above number-line graph:



Edwin