SOLUTION: How would I simplify and state the non-permissible values of these questions?
{{{4x/(x+2) + 3/(x+1)}}}
3x/x-4+6/x+2
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-> SOLUTION: How would I simplify and state the non-permissible values of these questions?
{{{4x/(x+2) + 3/(x+1)}}}
3x/x-4+6/x+2
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You can put this solution on YOUR website! simplify and state the non-permissible values of these questions?
4x/(x+2) + 3/(x+1)
The denominators cannot be zero.
x cannot be -2 ; x cannot be -1
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3x/(x-4) + 6/(x+2)
x cannot be 4 ; x cannot be -2
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Cheers,
Stan H.
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Division by zero is not defined in mathematics
So denominators can never be zero, so
The denominator x+2 can never equal to 0,
so we write x+2 ≠ 0 and solve for x
x ≠ -2
The denominator x+1 also can never equal to 0,
so we write x+1 ≠ 0 and solve for x
x ≠ -1
On a number line like this
--------------------------------
-6 -5 -4 -3 -2 -1 0 1 2 3 4
We put open circles at -2 and -1
-------------o--o---------------
-6 -5 -4 -3 -2 -1 0 1 2 3 4
and shade the rest, putting arrows at the ends,
pointing to negative infinity on the left and to
positive infinity on the right:
<============o==o==============>
-6 -5 -4 -3 -2 -1 0 1 2 3 4
The interval notation is an abbreviation of the
above number-line graph:
Edwin