SOLUTION: Mrs. Rifkin had 84 oranges. 24 of her oranges were rotten; the rest were either ripe or unripe. There were 18 more ripe oranges than unripe oranges. Find the ratio of the number of

Algebra ->  Finance -> SOLUTION: Mrs. Rifkin had 84 oranges. 24 of her oranges were rotten; the rest were either ripe or unripe. There were 18 more ripe oranges than unripe oranges. Find the ratio of the number of      Log On


   



Question 1033380: Mrs. Rifkin had 84 oranges. 24 of her oranges were rotten; the rest were either ripe or unripe. There were 18 more ripe oranges than unripe oranges. Find the ratio of the number of ripe oranges to the number of rotten oranges to the number of unripe oranges.
Answer by josgarithmetic(39623) About Me  (Show Source):
You can put this solution on YOUR website!
x rotten
y unripe
z ripe

system%28x%2By%2Bz=84%2Cx=24%2Cz=y%2B18%29

The question asks for z:x:y.