SOLUTION: For solving systems of linear equations. How do I write equations for this type of question?
The perimeter of a rectangle is 24ft. It's length is five times its width. Let x be th
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The perimeter of a rectangle is 24ft. It's length is five times its width. Let x be th
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Question 1033244: For solving systems of linear equations. How do I write equations for this type of question?
The perimeter of a rectangle is 24ft. It's length is five times its width. Let x be the length and y be the width. What is the area of the rectangle? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The perimeter of a rectangle is 24ft. It's length is five times its width. Let L be the length and W be the width. What is the area of the rectangle?
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Perimeter = 2(L + W)
L = 5W
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24 = 2(5W + W)
12 = 6W
Width = 2 ft
Length = 5W = 10 ft
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Cheers,
Stan H.
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