SOLUTION: The fish tank has side lengths 10in, 14in and height 15in . The water level is two inches below the top of the tank. A glass sphere of radius 3in is dropped in to the tank. What

Algebra ->  Surface-area -> SOLUTION: The fish tank has side lengths 10in, 14in and height 15in . The water level is two inches below the top of the tank. A glass sphere of radius 3in is dropped in to the tank. What       Log On


   

Question 1033232: The fish tank has side lengths 10in, 14in and height 15in .
The water level is two inches below the top of the tank.
A glass sphere of radius 3in is dropped in to the tank. What is the new distance from the water to the top of the tank? How many of these balls can be put into the tank with the tank not overflowing?
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
The easiest way is look at the vertical change in water level, in inches.

10%2A14%2Ad=%284%2F3%29pi%2A3%5E3

d=%284%2F3%29pi%2A27%2F%28140%29

d=9pi%2F35, the change in vertical water level.

That was not what the question asked for.


Volume of the sphere: 36pi
Empty Volume in the Tank: 10%2A14%2A2=280
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NOW the question asked how many spheres will fit before forcing the water to overflow?
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Meaning is, how many of 36pi is in 280?
280%2F%2836pi%29
70%2F%289pi%29
2.4757%2Aapproximately
but you can only use whole values, NO fractional parts.
2 glass spheres.