SOLUTION: 1. A system of equations, along with the solution, is shown in the introduction to this lesson. A+B=5 2B-C=3 5A+C=16 A=3 B=2 C=1 Explain how you would solve this system,

Algebra ->  Rational-functions -> SOLUTION: 1. A system of equations, along with the solution, is shown in the introduction to this lesson. A+B=5 2B-C=3 5A+C=16 A=3 B=2 C=1 Explain how you would solve this system,      Log On


   

Question 1033199: 1. A system of equations, along with the solution, is shown in the introduction to this lesson.
A+B=5
2B-C=3
5A+C=16
A=3 B=2 C=1

Explain how you would solve this system, and support each step by showing your work.



Answer by jorel555(1290) About Me  (Show Source):
You can put this solution on YOUR website!
A+B=5, So:
2A+2B=10
2B-C=3
2A+2B-(2B-C)=10-3=7
2A+C=7
5A+C=16
5A+C-(2A+C)=16-7=9
3A=9
A=3
B=2
C=1!!!!!!!!