SOLUTION: Find two consecutive odd integers such that the sum of one-third of the smaller number and four times the larger number is 73.

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Question 1033075: Find two consecutive odd integers such that the sum of one-third of the smaller number and four times the larger number is 73.
Answer by jorel555(1290) About Me  (Show Source):
You can put this solution on YOUR website!
Let n be our first integer. Our 2nd integer would then be n+2. Thus:
n/3+4(n+2)=73
n+12(n+2)=219
13n=195
n=15
n+2=17!!!!!!!!!!!!!