SOLUTION: The sum of two consecutive even integers is 2 more than twice the smaller integer. I tried to set it up as follows: x = first integer, x+2 = second x+x+2=2x=+2 but then it solve

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: The sum of two consecutive even integers is 2 more than twice the smaller integer. I tried to set it up as follows: x = first integer, x+2 = second x+x+2=2x=+2 but then it solve      Log On


   

Question 103303: The sum of two consecutive even integers is 2 more than twice the smaller integer. I tried to set it up as follows: x = first integer, x+2 = second
x+x+2=2x=+2 but then it solves to 0=0
Answer by HyperBrain(694) About Me  (Show Source):
You can put this solution on YOUR website!
Let x=the smaller no.
x+2=the larger no.
x%2B%28x%2B2%29=2%2B2x
2x%2B2=2x%2B2

Yup, you're right! This may reduce to 0=0. This doesn't mean that we're incorrect. This means that the problem has infinite solutions!--HyperBrain