SOLUTION: A bucket full of water is in the form of a frustum of a cone. The bottom and top radii of the frustum are 18cm and 28cm respectively and the vertical depth is 30cm. If the water in

Algebra ->  Surface-area -> SOLUTION: A bucket full of water is in the form of a frustum of a cone. The bottom and top radii of the frustum are 18cm and 28cm respectively and the vertical depth is 30cm. If the water in      Log On


   



Question 1033020: A bucket full of water is in the form of a frustum of a cone. The bottom and top radii of the frustum are 18cm and 28cm respectively and the vertical depth is 30cm. If the water in the bucket is then poured into an empty cylindrical container with base radius 20cm, find the depth of the water in the container. (Take pie=22 over7

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
V frustum of cone =
Volume of a conical frustum: ◦V = (1/3) * π * h * (r1^2 + r2^2 + (r1 * r2))
r1=18
r2=28
height = 30
V = %281%2F3%29+%2Api+%2A+30%2818%5E2+%2B28%5E2+%2B18%2A28%29
=50642.5 in^3
Volume of cylinder = 1/3 pi r^2h
50642.5 = (1/3) *pi*20^2*h
h= 50642.5*3/ (pi*20^2)
= 120.9 inches