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You have 33 quarters and dimes in a jar. The jar contains a total of $4.95. Write and solve a system of equations
to find the number x of dimes and the number y of quarters
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Another solution is like this:
Let d be the number of dimes.
Then the number of quarters is (33-d).
The dimes contribute 10*d cents into the total.
The quarters contribute 25*(33-d).
Altogether, the quarter and dimes comprise 495 cents, which gives you an equation
10*d + 25*(33-d) = 495.
Simplify and solve for d:
10d + 825 - 25d = 495, or
-15d = 495-825,
-15d = -330,
d =
= 22.
So, there are 22 dimes.
Then the number of quarters is 33 - 22 = 11.
Check. 22*10 + 11*25 = 495. OK!
Answer. 22 dimes and 11 quarters.