Question 1032953: What's the probability of at least one 3 in 10 rolls of a fair die? Found 2 solutions by FrankM, stanbon:Answer by FrankM(1040) (Show Source):
You can put this solution on YOUR website! This simplifies to 1-P(no 3s)
the probability of each roll being not 3 is 5/6, for 10 rolls, (5/6)^10 or .1615, 16.15% , a bit less than 1 in 6. But this is for no 3s.
1-.1615= .8385 or 83.85%
You can put this solution on YOUR website! What's the probability of at least one 3 in 10 rolls of a fair die?
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Binomial Problem with n = 10 ; p(x=3) = 1/6 ; p(x#3) = 5/6
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P(1<= x <= 10) = 1 - P(x = 0) = 1 - (5/6)^10 = 1-0.1615 = 0.8385
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Cheers,
Stan H.
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