SOLUTION: Twenty-three slips of paper are each marked with a different
letter of the alphabet and placed in a basket. A slip is pulled
out, its letter recorded (in the order in which the
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-> SOLUTION: Twenty-three slips of paper are each marked with a different
letter of the alphabet and placed in a basket. A slip is pulled
out, its letter recorded (in the order in which the
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Question 1032898: Twenty-three slips of paper are each marked with a different
letter of the alphabet and placed in a basket. A slip is pulled
out, its letter recorded (in the order in which the slip was
drawn), and the slip is replaced. This is done 44 times. Find
the probability that a word with no repetition of letters is
formed. Answer by Edwin McCravy(20055) (Show Source):
You can put this solution on YOUR website! Twenty-three slips of paper are each marked with a different
letter of the alphabet and placed in a basket. A slip is pulled
out, its letter recorded (in the order in which the slip was
drawn), and the slip is replaced. This is done 44 times. Find
the probability that a word with no repetition of letters is
formed.
Answer: 0.
There is no way to draw out 44 different letters when there are
only 23 different letters in the basket. There must be
repetitions.
Edwin
