SOLUTION: A ball is thrown into the air with an upward velocity of 48ft/s it's high eight in feet after T seconds is given by the function h=-16t^2+48x+6. How long does it take the ball to

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Question 1032890: A ball is thrown into the air with an upward velocity of 48ft/s it's high eight in feet after T seconds is given by the function h=-16t^2+48x+6. How long does it take the ball to reach its maximum height ? What is the balls maximum height ? Round to the nearest hundredth of necessary
Answer by stanbon(75887) About Me  (Show Source):
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ball is thrown into the air with an upward velocity of 48ft/s it's high eight in feet after T seconds is given by the function h=-16t^2+48x+6. How long does it take the ball to reach its maximum height ? What is the balls maximum height ? Round to the nearest hundredth of necessary
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Max occurs when t = -b/(2a) = -48/(2*-16) = 3/2 seconds
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Max height = h(3/2)
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Cheers,
Stan H.
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