SOLUTION: How do you solve this for x ? {{{ log ( 2 , 2x) }}} + {{{ log (2 , x) }}} = 5 I'm not really sure about how to even start off this problem but I feel like an e will be invol

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: How do you solve this for x ? {{{ log ( 2 , 2x) }}} + {{{ log (2 , x) }}} = 5 I'm not really sure about how to even start off this problem but I feel like an e will be invol      Log On


   

Question 1032859: How do you solve this for x ?
+log+%28+2+%2C+2x%29+ + +log+%282+%2C+x%29+ = 5

I'm not really sure about how to even start off this problem but I feel like an e will be involved. Please please help, thank you so much. :)
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
You do not need e here.

Use the fact that . So .

Since , we must have . Assuming we only define log on the positive real numbers, the only solution is (x = -4 introduces logs of negative numbers).