SOLUTION: Suppose 81^x = 64. What is 27^{x+1}?

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Question 1032657: Suppose 81^x = 64. What is 27^{x+1}?
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!

==> %2864%2A27%29%2F3%5Ex+=++27%5E%28x+%2B+1%29
But 3%5Ex+=+2sqrt%282%29.
==> 27%5E%28x+%2B+1%29+=+%2864%2A27%29%2F%282sqrt%282%29%29+=+432sqrt%282%29