SOLUTION: Let f(x) = 2x^2 − 8x − 7.
What is the quadratic in vertex form that is y = a(x − h)^2 + k
for some constants a, h, and k). Use the vertex form to locate the x
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-> SOLUTION: Let f(x) = 2x^2 − 8x − 7.
What is the quadratic in vertex form that is y = a(x − h)^2 + k
for some constants a, h, and k). Use the vertex form to locate the x
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Question 1032602: Let f(x) = 2x^2 − 8x − 7.
What is the quadratic in vertex form that is y = a(x − h)^2 + k
for some constants a, h, and k). Use the vertex form to locate the x intercepts of the function. (without the quadratic formula.) Sketch the graph of f, showing all important features. Solve f(x) > 0. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Let f(x) = 2x^2 − 8x − 7
2x^2 - 8x = y +7
2(x^2 - 4x + 4) = y + 7 + 2*4
y = 2(x-2)^2 - 15
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That is the quadratic in vertex form that is y = a(x − h)^2 + k
for some constants a, h, and k.
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Use the vertex form to locate the x intercepts of the function. (without the quadratic formula.)
Vertex is (2,-15)
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Sketch the graph of f, showing all important features.
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Solve f(x) > 0.
Cheers
Stan H.
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