SOLUTION: The length of a rectangle is four times its width. If the perimeter of the rectangle is 50 ft, find its area

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: The length of a rectangle is four times its width. If the perimeter of the rectangle is 50 ft, find its area      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1032419: The length of a rectangle is four times its width. If the perimeter of the rectangle is 50 ft, find its area
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
w width, L length;
L=4w

2w%2B2L=50
2w%2B2%284w%29=50
10w=50
w=5-----------meaning length is L=20.

Area is w%2AL.