SOLUTION: 4x^2+3y^2=4 2x-2y^2=-3

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Question 1032302: 4x^2+3y^2=4
2x-2y^2=-3
Answer by ikleyn(52794) About Me  (Show Source):
You can put this solution on YOUR website!
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4x^2 + 3y^2 =  4,    (1)
2x   - 2y^2 = -3.    (2)

From (2), express 2x = -3+%2B+2y%5E2. Now, substitute it into (1) by noting that 4x%5E2 = %282x%29%5E2. You will get a single equation for y%5E2:

%28-3%2B2y%5E2%29%5E2 + 3y%5E2 = 4.

Open parentheses, collect the like terms and introduce the new variable z = y%5E2.

Solve the obtained quadratic equation for z.

Then find "y" from z = y%5E2.

Then find "x" from (2).