SOLUTION: I submitted this before but my question got cut off somehow but here it is again. a 40 foot ladder is leaning against a building so that the distance from the bottom of the lad

Algebra ->  Length-and-distance -> SOLUTION: I submitted this before but my question got cut off somehow but here it is again. a 40 foot ladder is leaning against a building so that the distance from the bottom of the lad      Log On


   



Question 1032284: I submitted this before but my question got cut off somehow but here it is again.
a 40 foot ladder is leaning against a building so that the distance from the bottom of the ladder to the building is 8 feet more than the distance the ladder reaches up the building. find how far up the building the ladder reaches. I think the hypotenuse is 40 and one leg is x+8 but I'm not too sure.
Thank you for the help.

Answer by ikleyn(52788) About Me  (Show Source):
You can put this solution on YOUR website!
.
Let x = how far up the building the ladder reaches (vertical leg).
Then the other leg is (x+8).

The Pythagorean equation is 

x%5E2+%2B+%28x%2B8%29%5E2 = 40%5E2.

2x%5E2+%2B+16x+%2B+64 = 1600,

x%5E2+%2B+8x+-+768 = 0,

(x-24)*(x+32) = 0,

The only positive root is x = 24.

Check. 24%5E2+%2B+32%5E2 = 1600.