SOLUTION: If the squares of two consecutive positive integers differ by 1987, what is the sum of these two integers. Thanks

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Question 1032119: If the squares of two consecutive positive integers differ by 1987, what is the sum of these
two integers. Thanks

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!

Smaller integer = x
Larger integer = x%2B1
Square of smaller integer = x%5E2
Square of larger integer = %28x%2B1%29%5E2
Square of larger integer - Square of smaller integer = 1987

%28x%2B1%29%5E2-x%5E2%22%22=%22%221987
%28x%2B1%29%28x%2B1%29-x%5E2%22%22=%22%221987
x%5E2%2Bx%2Bx%2B1-x%5E2%22%22=%22%221987
2x%2B1%22%22=%22%221987
2x%22%22=%22%221986
x%22%22=%22%22993

Smaller integer = x = 993
Larger integer = x%2B1 = 993%2B1%29 = 994

The consecutive integers are 993 and 994.

Edwin