SOLUTION: The distance that a free falling object falls is directly proportional to the square of the time it falls (before it hits the ground). If an object fell 50 ft in 5 seconds, how fa
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Question 1032106: The distance that a free falling object falls is directly proportional to the square of the time it falls (before it hits the ground). If an object fell 50 ft in 5 seconds, how far will it have fallen by the end of 9 seconds? (Leave the variation constant in fraction form or round to at least 2 decimal places. Round your final answer to the nearest foot.) Found 3 solutions by josmiceli, ikleyn, MathTherapy:Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! .
The distance that a free falling object falls is directly proportional to the square of the time it falls (before it hits the ground).
If an object fell 50 ft in 5 seconds, how far will it have fallen by the end of 9 seconds? (Leave the variation constant in
fraction form or round to at least 2 decimal places. Round your final answer to the nearest foot.)
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I will not consider the solution of this problem, but I'd like to make a small notice.
Near the Earth surface, the free fall acceleration is 32 (approximately. See this article of Wikipedia).
Accordingly, the free falling body falls = 400 ft in the first 5 seconds.
You can put this solution on YOUR website!
The distance that a free falling object falls is directly proportional to the square of the time it falls (before it hits the ground). If an object fell 50 ft in 5 seconds, how far will it have fallen by the end of 9 seconds? (Leave the variation constant in fraction form or round to at least 2 decimal places. Round your final answer to the nearest foot.)
With D being distance, k: constant of proportionality, and T, time (in seconds), we get:
D = 2(81), or
