SOLUTION: Two jets leave an air base at the same time and travel in opposite directions. One jet travels 94 /mih slower than the other. If the two jets are 5216mi apart after 4

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Question 1032031: Two jets leave an air base at the same time and travel in opposite directions. One jet travels
94

/mih
slower than the other. If the two jets are
5216mi
apart after
4
hours, what is the rate of each jet?

Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
Since rate ties time equals distance, we can use that to solve this problem...
Call the rate of the slower jet, r.
Then the rate of the faster jet is r+94.
They both travel for four hours and the total distance covered is 5216 miles.
So we can write
4r + 4(r+94) = 5216
4r + 4r + 376 = 5216
8r + 376 = 5216
8r = 4840
r = 605 mph
so that
r+94 = 699 mph