SOLUTION: (cosx-secx)/secx = -sin^2x

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Question 1032013: (cosx-secx)/secx = -sin^2x
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
sin^2x=1-cos^2x
-sin^2x=cos^2x-1
(cosx-secx)/secx = -sin^2x
rewrite left side as
cosx/secx -1
but that is cos x/(1/cos x)=cos^2x
Therefore, the left side is cos^2x-1 which is -sin^2x