SOLUTION: 6x=(y-2)^2 How do I graph the parabola?

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: 6x=(y-2)^2 How do I graph the parabola?      Log On


   

Question 1031997: 6x=(y-2)^2 How do I graph the parabola?
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
This is a non-function with opening to the right and shifted two units up.
(y-2)^2=6x
y-2=+/-sqrt (6x)
y=2 +/- sqrt(6x)
graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C2%2Bsqrt%286x%29%2C2-sqrt%286x%29%29
Domain is x>=0
range is all real numbers
y-intercept is at 2 (0,2)
x-intercept is at x=2/3 (2/3,0)