SOLUTION: A metallurgist has one alloy containing 29% copper and another containing 53% copper. How many pounds of each alloy must he use to make 49 pounds of a third alloy containing 34% co
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Question 1031864: A metallurgist has one alloy containing 29% copper and another containing 53% copper. How many pounds of each alloy must he use to make 49 pounds of a third alloy containing 34% copper? (Round to two decimal places if necessary.) Answer by mananth(16946) (Show Source):
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Copper
percent ---------------- quantity
Alloy I 29.00% ---------------- x lb
Alloy II 53.00% ------ 49 - x lb
Mixture 34.00% ---------------- 49
49
29.00% x + 53.00% ( 49 - x ) = 34.00% * 49
29 x + 53 ( 49 - x ) = 1666
29 x + 2597 - 53 x = 1666
29 x - 53 x = 1666 - -2597
-24 x = -931
/ -24
x = 38.79 lb 29.00% Alloy I
10.21 lb 53.00% Alloy II
