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| Question 1031842:  Carlee (again!) is spinning a spinner marked with the letters a  through f . She defines the events A={a,b,c,d}  and B={c,d,e} . Suppose that P(a)=0.02 , P(b)=P(c)=0.1 , P(d)=0.11 , and P(e)=0.04 .
 (a)  P(A)=
 (b)  P(B)=
 (c)  P(A∩B)=
 (d)  P(A|B)=
 (e)   P(B|A)=
 (f)   Are A  and B  independent? Your answer should be "Y" or "N".
 Answer by stanbon(75887)
      (Show Source): 
You can put this solution on YOUR website! Carlee (again!) is spinning a spinner marked with the letters a through f . She defines the events A={a,b,c,d} and B={c,d,e} . Suppose that
 P(a)=0.02 ,
 P(b)=P(c)=0.1 ,
 P(d)=0.11 ,
 and P(e)=0.04 .
 (a) P(A)= 0.02+0.10 + 0.10 + 0.11 = 0.33
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 (b) P(B)= 0.10 + 0.11 + 0.04 = 0.25
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 (c) P(A∩B)= P{c,d} = 0.10+0.11 = 0.21
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 (d) P(A|B)= P(A and B)/P(B) = 0.21/0.25
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 (e) P(B|A)= P(A and B)/P(A) = 0.21/0.33
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 (f) Are A and B independent? Your answer should be "Y" or "N".
 Question:: P(A|B) = P(A)*P(B)
 0.21/0.25 = 0.33*0.25
 0.84 = 0.0825
 Ans:: not equal
 Ans: A and B are not independent
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 Cheers,
 Stan H.
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