SOLUTION: How would you solve the equation 4e^x+1=5

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Question 1031778: How would you solve the equation
4e^x+1=5
Found 3 solutions by addingup, ikleyn, MathTherapy:
Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x:
(4e^x)+1=5
I'll restate it this way:
1+4e^x = 5
Now subtract 1, both sides:
4e^x = 4
divide both sides by 4:
e^x = 1
To eliminate the exponent on the left, take the log_n both sides:
x = (2i)Pi*n
Good luck,
John

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
Actually, the solution is x = 0.


Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

How would you solve the equation
4e^x+1=5 
4e%5Ex+%2B+1+=+5

4e%5Ex+=+4 ------- Subtracting 1

e%5Ex+=+4%2F4 -------- Dividing by 4

e%5Ex+=+1

ln 1 = x ------- Converting to LOGARITHMIC (Natural) form

highlight_green%280+=+x%29