SOLUTION: How would you find the domain of :
h(x)=3-2log base 4 {(x-2)-5}
Doman had always been one of my worst enemies :(((((
so any help would be greatly appreciated
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Exponential-and-logarithmic-functions
-> SOLUTION: How would you find the domain of :
h(x)=3-2log base 4 {(x-2)-5}
Doman had always been one of my worst enemies :(((((
so any help would be greatly appreciated
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Question 1031775: How would you find the domain of :
h(x)=3-2log base 4 {(x-2)-5}
Doman had always been one of my worst enemies :(((((
so any help would be greatly appreciated Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website! you can't take the log of a negative number or 0, therefore the expression within the log function sign has to be greater than 0.
this means that (x-2)-5 has to be greater than 0.
(x-2)-5 is the same as x-7 so you get x-7 has to be greater than 0.
this means that x has to be greater than 7.
here's the graph of that equation.
there is an asymptote at x = 7.
the graph is only valid when x > 7.
this is because you can't take the log of a negative number or 0 and get a real answer that can be graphed on the real plane.
log((x-2)-5) = log(x-7).
x-7 > 0 results in x > 7.
your domain is all real values of x such that x > 7.
