SOLUTION: The length of each leg of an isosceles triangle is 7 inches less than twice the length of the base. If the perimeter of this isosceles triangle is 61 inches, what is the length of
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Question 1031708: The length of each leg of an isosceles triangle is 7 inches less than twice the length of the base. If the perimeter of this isosceles triangle is 61 inches, what is the length of the base? Answer by mananth(16946) (Show Source):
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length of the base= x
The length of each leg of an isosceles triangle is 7 inches less than twice the base
leg = 2x-7
If the perimeter of this isosceles triangle is 61 inches,
2x-7 + 2x-7 +x = 61
5x-14 =61
5x=75
x=75/5
x= 15 the length of the base in inches
