SOLUTION: The base of a particular parallelogram is 4 times its height. If the base and height are doubled, the new area is 972 square inches greater than the area of the original parallelo

Algebra ->  Equations -> SOLUTION: The base of a particular parallelogram is 4 times its height. If the base and height are doubled, the new area is 972 square inches greater than the area of the original parallelo      Log On


   



Question 1031701: The base of a particular parallelogram is 4 times its height. If the base and height are doubled, the new area is 972 square inches greater than the
area of the original parallelogram. Find the base and height of the original parallelogram.

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
The base of a particular parallelogram is 4 times its height.
Area = b * h
b=4h
Area = 4h*h = 4h^2
the new height = 2h
and new base = 8h
Area = 16h^2
16h^2 = 4h^2 +972
12h^2 = 972
h^2= 81
h= 9 taking positive value
height = 9 in
and base = 9*4 = 36 in