SOLUTION: please help me with this problem: Differentiate: y = {{{ln(x^2 + 1) + (x + 1)/(e^x + 1)}}}

Algebra ->  Test -> SOLUTION: please help me with this problem: Differentiate: y = {{{ln(x^2 + 1) + (x + 1)/(e^x + 1)}}}      Log On


   



Question 1031665: please help me with this problem:
Differentiate: y = ln%28x%5E2+%2B+1%29+%2B+%28x+%2B+1%29%2F%28e%5Ex+%2B+1%29

Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
derivative of ln((x^2)+1) = 2x / (x^2+1)
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use definition of derivative of log
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derivative of (x+1) / ((e^x)+1) = ((x+1) / ((e^x)+1)^2) - (x / ((e^x)+1))
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use definition of derivative of a quotient
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put them together and we have
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y' = (2x / (x^2+1)) + ((x+1) / ((e^x)+1)^2) - (x / ((e^x)+1))
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no assumption on x being < 0 or > 0
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